lcp362

8029. 与车相交的点

方法一:差分数组

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class Solution {
public int numberOfPoints(List<List<Integer>> nums) {
int n = nums.size(), cnt = 0;
int[] diff = new int[103];
for (List<Integer> list : nums) {
diff[list.get(0)]++;
diff[list.get(1) + 1]--;
}
int s = 0;
for (int i = 0; i < diff.length; ++i) {
s += diff[i];
if (s > 0)
++cnt;
}
return cnt;
}
}

8049. 判断能否在给定时间到达单元格

方法一:数学

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class Solution {
public boolean isReachableAtTime(int x, int y, int fx, int fy, int t) {
if (x == fx && y == fy && t == 1)
return false;
int a = Math.abs(fx - x), b = Math.abs(fy - y), min = Math.min(a, b);
t -= min;
a -= min;
b -= min;
t = t - a - b;
return t >= 0;
}
}
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List<int[]> map0 = new ArrayList<>(), map2 = new ArrayList<>();
int n, m;

public int minimumMoves(int[][] grid) {
for (int i = 0; i < 3; ++i) {
for (int j = 0; j < 3; ++j) {
if (grid[i][j] == 0)
map0.add(new int[]{i, j, 0});
else if (grid[i][j] > 1)
map2.add(new int[]{i, j, grid[i][j]});
}
}
if (map0.isEmpty())
return 0;
n = map2.size();
m = map0.size();
int res = 0;
Queue<int[]> queue = new LinkedList<>();
boolean[][] visited = new boolean[3][3];
return dfs(0, 0, visited);

}

private int dfs(int i, int j, boolean[][] visited) {
if (i == map2.size())
return 0;
if (j == map0.size())
return map2.get(i)[2] == 1 ? 0 : Integer.MAX_VALUE / 2;
int[] x = map2.get(i), y = map0.get(j);
int pass = dfs(i, j + 1, visited), choose = Integer.MAX_VALUE / 2;
if (x[2] > 1) {
if (visited[y[0]][y[1]])
choose = dfs(i, j + 1, visited);
else {
visited[y[0]][y[1]] = true;
map2.get(i)[2]--;
choose = dfs(i, j + 1, visited) + Math.abs(x[0] - y[0]) + Math.abs(x[1] - y[1]);
map2.get(i)[2]++;
visited[y[0]][y[1]] = false;
}
}
else if (x[2] == 1) {
int xx = dfs(i + 1, 0, visited);
choose += xx;
pass += xx;
}
return Math.min(pass, choose);
}

private boolean isValid(int i, int j) {
return i >= 0 && j >= 0 && i < 3 && j < 3;
}

int[][] dirs = new int[][]{{-1, 0}, {1, 0}, {0, -1}, {0, 1}};


lcp362
https://leopol1d.github.io/2023/09/10/lcp362/
作者
Leopold
发布于
2023年9月10日
许可协议